Bear Creek Reservoir Topics: Easy One -

Bear Creek Reservoir Topics

(Bear Creek Reservoir Specific)

9 messages

Updated 11/3/2023 6:12:58 AM

Off-Topic

Lakes Online Forum

83,627 messages

Updated 5/20/2024 12:16:20 AM

Boat Maintenance

Lakes Online Forum

5,193 messages

Updated 4/3/2024 3:47:36 AM

Bear Creek Reservoir Fishing

(Bear Creek Reservoir Specific)

0 messages

Updated

Jokes

Lakes Online Forum

4,169 messages

Updated 4/15/2024 11:05:05 PM

Sports

Lakes Online Forum

4,260 messages

Updated 3/24/2024 9:24:45 AM

Grilling & Recipes

Lakes Online Forum

2,976 messages

Updated 3/20/2024 11:53:43 PM

Tallapoosa River Topics

Lakes Online Forum

98 messages

Updated 4/15/2024 1:00:58 AM

Forum Usage Rules

Welcome, Guest

Select View Mode: [ classic | beta | recent ]

	Name:	PikeSki -
	Subject:	Easy One -
	Date:	2/16/2006 4:48:21 PM

Any number of flowers (equal in each vase) will work.

Example:

If each vase starts out with 3 flowers that is 3+3+3
The starting average per vase is 3
3+3+3=9 divided by 3 vases

If she adds 3 flowers to the 1st vase that is:
3+3(Vase1)+3 (second vase) + 3 (third vase).

To find the new average you would add (3+3)+3+3=12 flowers
3 vases divided by 12 flowers = 4 (new average)

Answer: Vase 1 now has 6 total flowers which is 2 more than the new average.

NOTE - Any number of flowers in each vase will work for this.

What do I win?